Topic 10 · page 2 of 27

Mechanisms and curly arrows

A mechanism is a step-by-step account of which bonds break and which form. Curly arrows show a pair of electrons moving, and breaking a bond unevenly, heterolytic fission, makes ions.

12 min read10.210.3

Read first: Seven types of reaction

What a mechanism shows 10.2

An equation says what you start with and what you finish with. It does not say how. A mechanism shows how, one step at a time, by following the electrons.

A mechanism has four parts. You will use all four in this topic.

Some mechanisms take one step and some take two. The electrophilic addition of Topic 5 took two steps with a carbocation between them. The substitutions on pages 9 and 10 are drawn as one step (hydroxide) and two steps (ammonia).

Curly arrows 10.2

A curly arrow shows where a pair of electrons moves.

Rule What it means
The arrow shows a pair of electrons it has a full head. A half-headed arrow shows one electron, which is for the radical reactions of Topic 4
It starts at a bond or at a lone pair never at an atom symbol, and never at a + or − charge
It ends at the atom that receives the pair, or in the gap where a new bond forms the head touches the atom or points at the gap
Charges balance afterwards the atom that gains a pair becomes more negative, the atom that loses it more positive
A generic substitution drawn twice. Left: a lone pair on a nucleophile, Nu, has a curly arrow pointing to the carbon of a C-X bond, so the arrow starts at the lone pair and ends at the gap where a new Nu-C bond forms. Right: a curly arrow starts in the middle of the C-X bond and points to X, the atom that takes both electrons.
The two kinds of curly arrow in this topic. Left: from a lone pair to the atom it will bond to. Right: from a bond to the atom that takes both electrons away.

In nearly every mechanism in this topic there are two such arrows. One starts at a lone pair and forms a new bond. One starts at a bond and breaks it.

Heterolytic fission makes ions 10.3

When a covalent bond breaks, its two electrons must go somewhere.

The atom that takes the pair is the more electronegative one. In the C–Br bond that is bromine.

Heterolytic fission of the C-Br bond in bromoethane. One curly arrow starts in the middle of the C-Br bond and points to the bromine atom. The products are a positive ethyl carbocation, CH3CH2 with a plus charge, and a bromide ion Br with four lone pairs and a minus charge. Labels: the carbocation is an electrophile, the bromide ion has lone pairs.
Heterolytic fission of C–Br. The arrow starts at the bond and ends at Br. Br⁻ keeps the pair of electrons.
CHX3CHX2−Br→CHX3CHX2X++BrX− \ce{CH3CH2-Br -> CH3CH2+ + Br-}

The two ions are very different:

Check yourself

  1. Define the term reaction mechanism.
  2. State where a curly arrow must start, and where it must end.
  3. A student starts an arrow on the minus sign of a bromide ion. Explain what is wrong and how to correct it.
  4. What does a curly arrow with a full head show, and what does one with a single barb show?
  5. Draw the heterolytic fission of the C–Cl bond in chloroethane, CH₃CH₂Cl. Show the curly arrow and the charges on both products.
  6. Explain why bromine, not carbon, takes the electrons when C–Br breaks heterolytically.

Answers cover these until you have tried the questions

  1. A reaction mechanism is a step-by-step account of how bonds break and form as reactants become products, using curly arrows to show the movement of electron pairs.
  2. It must start at a bond or a lone pair, and end at the atom that receives the pair, or at the gap where the new bond forms.
  3. An arrow must start at a lone pair or a bond, not at a charge. Draw the lone pair on Br⁻ as two dots and start the arrow there.
  4. A full head shows the movement of a pair of electrons. A single barb (a half arrow) shows one electron, in a radical reaction.
  5. CH₃CH₂–Cl, with one full arrow from the middle of the C–Cl bond to the Cl atom. Products: CH₃CH₂⁺ (positive charge on carbon) and Cl⁻ (four lone pairs, negative charge).
  6. Bromine is more electronegative than carbon (2.8 against 2.5), so it attracts the bonding pair more strongly. It takes both electrons and becomes Br⁻.