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Constants and conversions

Quantity Value
Avogadro constant, L 6.02 × 10²³ mol⁻¹
molar volume at RTP 24.0 dm³ mol⁻¹ = 24 000 cm³ mol⁻¹
gas constant, R 8.31 J mol⁻¹ K⁻¹
temperature K = °C + 273
pressure Pa = kPa × 10³
volume dm³ = cm³ ÷ 1000; m³ = dm³ ÷ 1000 = cm³ × 10⁻⁶
ppm and % ppm = % × 10⁴

The equations

To find Use Page
amount from mass n = m ÷ M Relative mass and the mole
number of particles N = n × L Relative mass and the mole
amount in solution n = c × V (V in dm³) Solutions and ppm
mass concentration g dm⁻³ = mol dm⁻³ × M Solutions and ppm
parts per million part ÷ whole × 10⁶ Solutions and ppm
amount of gas at RTP n = V ÷ 24.0 (V in dm³) Gas volumes
amount of gas, any conditions pV = nRT (Pa, m³, K) Gas volumes
molar mass of a vapour M = mRT ÷ pV Gas volumes
percentage yield actual ÷ theoretical × 100 Yield and atom economy
atom economy M(desired) ÷ ΣM(all products) × 100 Yield and atom economy
The mole map: amount in moles in the centre, linked to mass, particles, gas volume and solution.
Into moles, across the equation, out of moles.

Definitions to learn word for word

Methods

The ten traps

  1. Changing a subscript instead of a coefficient to balance an equation.
  2. Writing H₂O(aq), or (aq) for a precipitate.
  3. Splitting a solid (CaCO₃, CuO, AgCl) into ions in an ionic equation.
  4. Using M = 16.0 for oxygen gas instead of 32.0.
  5. Multiplying M by the coefficient in a reacting-mass calculation.
  6. Rounding 1.5 or 1.33 to a whole number in an empirical formula.
  7. Leaving volumes in cm³ in c = n ÷ V or pV = nRT.
  8. Using kPa or °C in pV = nRT.
  9. Forgetting the coefficients in atom economy.
  10. Naming a product ("hydrogen forms") when asked for an observation ("fizzing").

Mixed test

Try these with no notes, then check the answers.

  1. Write the ionic equation, with state symbols, for zinc reacting with dilute hydrochloric acid.
  2. What mass of calcium carbonate is needed to make 2.40 dm³ of CO₂ at RTP, with excess acid?
  3. 0.200 g of a volatile liquid gives 61.0 cm³ of vapour at 373 K and 101 kPa. Calculate its molar mass.
  4. A compound is 52.2% carbon, 13.0% hydrogen and 34.8% oxygen by mass. Find its empirical formula.
  5. 25.0 cm³ of a solution contains 0.00500 mol of sodium carbonate. Give its concentration in mol dm⁻³ and in g dm⁻³.
  6. Calculate the atom economy for making ammonia: N₂ + 3H₂ → 2NH₃. Explain your answer.
  7. Barium chloride solution is added to a solution of magnesium sulfate. Give the observation and the ionic equation.
  8. Seawater contains about 0.40 g of potassium in every 1.0 kg. Express this in ppm.

Answers cover these until you have tried the questions

  1. Zn(s)+2 HX+(aq)→ZnX2+(aq)+HX2(g)\ce{Zn(s) + 2H+(aq) -> Zn^2+(aq) + H2(g)}
  2. n(CO₂) = 2.40 ÷ 24.0 = 0.100 mol = n(CaCO₃). m = 0.100 × 100.1 = 10.0 g
  3. n = (101 000 × 61.0 × 10⁻⁶) ÷ (8.31 × 373) = 1.99 × 10⁻³ mol. M = 0.200 ÷ 1.99 × 10⁻³ = 101 g mol⁻¹
  4. C: 52.2 ÷ 12.0 = 4.35. H: 13.0 ÷ 1.0 = 13.0. O: 34.8 ÷ 16.0 = 2.175. ÷ 2.175: 2 : 6 : 1, so C₂H₆O.
  5. c = 0.00500 ÷ 0.0250 = 0.200 mol dm⁻³. M(Na₂CO₃) = 106.0 g mol⁻¹, so 0.200 × 106.0 = 21.2 g dm⁻³
  6. 100%. Ammonia is the only product, so all the mass of the reactants ends up in the desired product.
  7. A white precipitate. BaX2+(aq)+SOX4X2−(aq)→BaSOX4(s)\ce{Ba^2+(aq) + SO4^2-(aq) -> BaSO4(s)}
  8. 0.40 ÷ 1000 × 10⁶ = 400 ppm (4.0 × 10² ppm)